WPP#10: Unit L Concept 9-14: Basic probability(one event), probability of independent "AND" events(multiple events with and without replacement), probability of "OR" events(mutually and non-mutually exclusive), and probability of events that require Combinations to determine sample space

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WPP#9: Unit L Concept 4-8: Calculating possibilities with FCP, combinations(one event and multiple events), permutations, and distinguishable permutations

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SP#6: Unit K Concept 10: Writing a repeating decimal as a rational number using geometric series

The viewer needs to be careful to not forget to add in the 6 at the end of the fraction(13/99). Also, the viewer needs to make sure that they wrote their first term as a fraction by just putting the term over 100,since the decimal is rounded to the hundreds. Lastly, the viewer needs to make sure they know the difference between summation notation and the summation formula.

Fibonacci Beauty Ratio (Extra Credit)

Chelsea A. Foot to Navel: 99 cm   Navel to top of Head: 62 cm   Ratio: 99/62=1.60 cm
Navel to chin: 40 cm                      chin to top of head: 21 cm       Ratio:40/21=1.90 cm
Knee to navel: 53 cm                      Foot to knee: 49 cm                Ratio: 53/49=1.08 cm

Average: 1.53 cm

Diana P. Foot to Navel: 100 cm   Navel to top of Head: 65 cm   Ratio: 100/65=1.54cm
Navel to chin: 44 cm                      chin to top of head: 20 cm       Ratio:40/20=2.2 cm
Knee to navel: 53 cm                      Foot to knee: 49 cm                Ratio: 53/49=1.08 cm

Average: 1.61 cm

Helena C. Foot to Navel: 101 cm   Navel to top of Head: 63 cm   Ratio: 101/63.=1.60 cm
Navel to chin: 46 cm                      chin to top of head: 19 cm       Ratio:46/19=2.42 cm
Knee to navel: 57 cm                      Foot to knee: 49 cm                Ratio: 57/49=1.16 cm

Average: 1.73 cm

Tracey P. Foot to Navel: 102 cm   Navel to top of Head: 63 cm   Ratio: 102/63=1.6 cm
Navel to chin: 43 cm                      chin to top of head: 21 cm       Ratio:43/21=2.05 cm
Knee to navel: 52 cm                      Foot to knee: 48 cm                Ratio: 52/48=1.08 cm

Average: 1.58 cm

Melissa A. Foot to Navel: 103 cm   Navel to top of Head: 63 cm   Ratio: 103/63=1.63 cm
Navel to chin: 45 cm                      chin to top of head: 19 cm       Ratio:45/19=2.37 cm
Knee to navel: 54 cm                      Foot to knee: 50 cm                Ratio: 54/50=1.08 cm

Average: 1.69 cm

According to Fibonacci's Golden Ratio, Diana P. is the most beautiful person out of this list because she was the closest to the number  1.6180339887. I believe the Beauty Ratio is very interesting because everything in our body is proportional. It makes me realize that the human body is very unique and valuable and that everything was made for a specific reason. It also makes me realize that we find something disproportional to be ugly. For example, if someone has a big nose they want to get cosmetic surgery to reshape their nose to make it proportional to their face. Therefore, I think the Beauty Ratio is only one factor of what makes someone beautiful.

Fibonacci Haiku: No Pardoning the Turkey

Thanksgiving 

Turkey

No school

Eating too much

Leftovers for a whole month

Mashed potatoes are essential for a delicious dinner

http://www.bing.com/images/search?q=turkey+clipart&qs=HS&form=QBIR&pq=turke&sc=8-5&sp=1&sk=#view=detail&id=5585B25828A7AF204C4E066D44A05EF1302A4FDA&selectedIndex=23

SP#5: Unit J Concept 6: Partial fraction decomposition with repeated factors

The viewer needs to pay close attention into inputting the coefficients of the system correctly. Also, the viewer needs to be very careful to not make the mistake of just distributing the square to the x and -2. It is not x^2+4, instead it is (x-2)times(x-2). Finally, the viewer need to not leave out a negative when combining like terms.

SP#4: Unit J Concept 5: Partial fraction decomposition with distinct factors

The viewer needs to pay special attention to first multiplying the expressions first and then distributing the number up at top in part 1 of the problem in order to correctly solve this problem. Next, the viewer needs to be careful when combing like terms because negatives can be easily lost since there are many numbers. Lastly, in part 2 of the problem the viewer needs to remember to get rid of the x's and x^2's when writing the system.